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x^2-0.72x-0.1152=0
a = 1; b = -0.72; c = -0.1152;
Δ = b2-4ac
Δ = -0.722-4·1·(-0.1152)
Δ = 0.9792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.72)-\sqrt{0.9792}}{2*1}=\frac{0.72-\sqrt{0.9792}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.72)+\sqrt{0.9792}}{2*1}=\frac{0.72+\sqrt{0.9792}}{2} $
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